Fibonacci Day 2021 is on Tuesday, November 23, 2021: fibonacci numbers?
Tuesday, November 23, 2021 is Fibonacci Day 2021. Fibonacci Day - the year of LIVING UNOFFICIALLY Fibonacci Day
Leonardo of Pisa, also known as Fibonacci, accounts for the Fibonacci Sequence (or Fibonacci amounts) – a design of counting where each number is the sum previous two. In addition to being prevalent in character, this type of product is used broadly in data storage and processing, and Fibonacci Day recognises the significance and cost of Fibonacci’s contributions to mathematics.
Fibonacci was a lovely man of the thirteenth century who had a
profound influence introducing us westerners to the digits
1,2,3,4,5,6,7,8,9, and 0! Do a google on him and spend the rest
of your life studying him and the Journals devoted to his work.
for some modern day uses of Fibonacci numbers.
all right, merlin is taking a journey from spain to china, and every day he gets younger (because he's experiencing time backwards), so each day he is able to cover the same distance he traveled the previous day plus the distance he traveled the day before that. if he travels 4 miles the first day and 7 miles the second day, how many days will it take him to reach his destination in china, which is 6,000 miles away?
ANS: 15 days. the sequence up to 15 is:
4, 7, 11, 18, 29, 47, 76, 123, 199, 322, 521, 843, 1364, 2207, 3571
and you have to add all those numbers up (after 14 days you get 5771, which is not enough; after 15 days you get 9342).
I don't know what you means by nature object??? But the example I heard was with rabbits. Say I release a pair of baby rabbits in Australia, and that they can start reproducing 2 days after they are born.
On day 0, there is 1 pair.
On day 1, there is 1 pair.
Then they reproduce to make another pair...
On day 2, there are 2 pairs.
On day 3, there are 3 pairs (the original pair repredoced, the other pair is still too young).
On day 4, there are 5 pairs (two pairs reproduced).
If you continue, you get,
Which is the Fibonacci sequence.
The idea is that
(Rabits on next day) = (Rabits on previous day) + (new reproduced pairs)
(Rabits on next day) will be the next term in the sequence. (Rabits on previous day) is the previous term in the sequence. The number of new pairs we get are the number of pairs that can reproduce, which is the number of pairs 2 days ago (so the term before last). So, we have,
F(n) = F(n-1) + F(n-2),
when F(n) is the nth term. Our starting conditions are F(0) = 1 and F(1) = 1